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Indefinite Integration
Basic Concept Let F(x) be a differentiable function of x such that . Then F (x) is called the integral of f(x). Symbiotically, it is written as  f (x), the function to be integrated is called the integrand. F(x) is also called the anti-derivate (or primitive function) of f (x).
Constant of Integration: As the differential coefficient of a constant is zero, we have
 This constant c is called the constant of integration and can take any real value.
Properties of Indefinite Integration

Basic Formulae










Method of Integration: If the integrand is not a derivative of a known function, then the corresponding integrals cannot be found directly. In order to find the integral of complex problems, generally three rules of integration are used. - Integration by substitution or by change of the independent variable.
- Integration by parts.
- Integration by partial fractions.
Integration by substitution There are following types of substitutions –– If integral is of the form , then put g ( x ) = t , provided exists 
- For terms of the form x2 + a2 or
put x = a tan or a cot  - For terms of the form x2 - a2 or
put x = a sec or a cosec  - For terms of the form a2 - x2 or
put x = a sin or a cos  - If both
are present then put x = a cos  - For the type
put x = a cos2 + b sin2  - For the type
put the expression within the bracket = t - For the type
put - For
again put (x + a) = t (x + b) –– If the integrand is of the form f ( x ) g ( x ), where g ( x ) is a function of the integral of f ( x ), then put integral of f ( x ) = t . e.g. Evaluate 
Sol. Integral of the numerator = 
Put x3/2 = t We get l = 
–– Some time it is useful to write the integral as a sum of two related integrals which can be evaluated by making suitable substitutions. Examples of such integrals are: A. Algebraic Twins

Method:
* Make the integration in the form 
or 
*If 
is present then put 
If 
is present then put
B. Trigonometric twins


Integration by Parts
1. If u and v be two function of x , then integral of product of these two functions is given by

Note:
In applying the above rule care has to be takne in the selection of the first function ( u ) and the second function ( v ). Normally we use the following methods: ( i ) If in the product of two functions, one of the functions in not directly integrable ( e.g. sin -1x , cos -1x , tan -1 x etc.) then we take it as the first function and the remaining function is taken as the second function e.g. In the integration 
x tan -1x dx, tan -1 x is taken as the first function and x as the second function. ( ii ) If there is no other function, then unity is taken as the second function e.g. In the integration of 
tan -1x dx, tan -1 is taken as the first function and 1 as the second function. ( iii ) If both of the function are directly integrable then the first function is chosen in such a way that the derivative of the function thus obtained under integral sign is easily integrable. Usually we use the following preference order for the first function (inverse, Logarithmic, Algebraic, Trigonometric, Exponential) In the aove stated order, the function on the left is always chosen as the first function. This rule is called as ILATE e.g. In the integration of 
x sin x dx, x is taken as the first function and sin x is taken as the second function.
Important Result: *
In the integral , if g ( x ) ex dx, if g(x) cna be expressed as g ( x ) = f ( x ) + f '( x ) then 
Some times to solve integral of the form 
we write it as 
and solve the integral with the help of integration by parts, taking 
as the first function. e.g.

is solved by writting it as 
and this integral can be solved by parts.
Algebraic Integrals
I. Integral of the form

In these types of integrals we write px + q = l (diff. coefficient of ax2 + bx + c ) + m Find l and m by comparing the coefficient of x and constant term on both sides of the identify. In this way the question will reduce the sum of two integrals which can be integrated easily. Integral of the type 
In this case substitute ax2 + bx + c = M ( px2 + qx + r ) + N (2 px + q ) + R Find M, N and R . The integration reduces to integration of three independent functions.
II. Integration of Irrational Algebraic Fractions
1. Rational fucntion of ( ax + b ) 1/n and x can be easily evaluated by the substitution tn = ax + b . Thus 
2. In the integration of 
the substitution x - k = 1 /t reduces the integration 
to the problem of integrating an expression of the form 
3. . 
Here we substitute, x - k = 1/ t . This substitution will reduce the given integral to 
4. To integrate 
we first put x = 1/ t , so that ––––––––––– 
Now the substitution C + Dt2 = u2 reduces it to the form  III. Integration of the function of the type
, 
Where m, n, p are rational numbers This integral is expressed through elementary functions only if one of the following conditions is fulfilled: (1) If p is an integer, (2) If 
is an intger, (3) If 
+ p is an integer. 1st case : (a) If p is a positive integer, remove the brackets (a + bxn)p according to the Newton binomial and calculate the integrals of powers. (b) If p is a negative integer, then the substitution x = tk, where k is the common denominator of the fractions m and n, leads to the integral of a rational fraction; 2nd case :
If 
is an integer, then the substitution a + bx n = t k is applied, where k is the denominator of the fraction p;
3rd case :
If 
+ p is an integer, then the substitution a + bx n = xnt k is applied, where k is the denominator of the fraction p. Example :
(i) 
(ii) 
(iii) 
(iv) 
Trignometric Integrals I. Integral of the form 
Universal substitution tan . 
In this case sin x = 
; cos x = 
, x = 2 tan- 1 t ; dx = 
If R (- sin x, cos x) = - R (sin x, cos x), then the substitution cos x = t is applied. If R (sin x, - cos x) = - R (sin x, cos x), then the substitution sin x = t is applied. If R (- sin x, - cos x) = R (sin x, cos x), then the substitution tan x = t is applied. II. Integral of the form
(i) 
(ii) 
dx (iii) 
dx (iv) 
This type of integration can be solved by converting the Nr in the form Nr = P(Dr) + Q + R the value of P, Q, R can be findout by comparing the coeffcient of both sides.
III. Integral of the form
(i) 
(ii) 
(iii) 
Transform the product of trigonometric function into a sum or difference, using one of the following formulas: sin ax sin bx = [cos(a-b) x - cos (a+b)x] cos ax cos bx = [cos (a - b) x + cos (a + b) x] sin ax cos bx = [sin (a - b) x + sin (a + b) x] IV. Integral of the form 
, where m and n are integers. (i) If m is an odd positive number, then apply the substitution cos x = t. (ii) If n is an odd positive number, apply the substitution sin x = t. (iii) If m and n are even non-negative numbers, use the formulas 
(iv) 
where (o < x < ?/2) and p and q are rational numbers. Substitute sin x = t
V. Integral of the form
– 
= when
VI. Integral of the form (i) 
(ii) 
(iii) 
(iv) 
This type of integration can be solved by multiplying sec 2 x, in N r and D r and substituting tan x = t, or cot x = t.
VII. Integral of the form
(i) 
(ii) 
(iii) 
To solve this type of integration 1) convert sinx and cosx in terms of tan x/2 by putting.

2) Write N r in the form sec 2 x/2 and Dr in the form tan x/2. 3) Substitute tan x/2 = t, so that sec 2 x/2 dx = 2dt
VIII.
If D r is in the form K + L sin x cos x, then Nr must be in the form of sin x + cos x, or sin x - cos x. (1) If N r has sin x + cos x then substitute sin x - cos x = t 
(cos x + sin x ) dx = dt (2) Nr has sin x - cos x then substitute sin x + cos x = t 
(cos x - sin x ) dx = dt Note: If sin x - cos x = t 1 - sin 2 x = t2 
sin 2 x = 1 - t2 If sin x + cos x = t 1 + sin 2 x = t2 sin 2 x = t2 - 1
INTEGRATION BY Partial fraction
Let 
is a proper algebric function. The partial fractions depend on the nature of the factors of Q ( x ). We have deal with the following different type when the factors of Q ( x ) are (i) Linear and non-repeated (ii) Linear and repeated (iii) Quadratic and non-repeated (iv) Quadratic and repeated
Case I :
When denominator is expressible as the product of non-repeated linear factors : Let Q (x) = (x - a 1 ) (x - a 2 ) (x - a 3 ) ... (x - a n ). Then we assume that ;

where A 1 , A 2 , ...., A n are constants and can be determined by equating numerator on R.H.S to numerator on L.H.S. and then substituting x = a 1 , a 2 , .... a n ,
Case II :
When the denominator Q ( x ) is expressible as the product of the linear factors such that some of them are repeating. (Linear and Repeated) Let, Q(x) = (x-a) k (x-a 1 ) (x-a 2 ) ... (x-a r ). Then we assume that 
Case III :
When some of the factors in denominator are quadratic but non-repeating. Corresponding to each quadratic factor ax 2 + bx + c, we assume the partial fraction of the type 
, where A and B are constants to be determined by comparing coefficients of similar powers of x in numerator of both sides.
Case IV :
When some of the factors of the denominator are quadratic and repeating. For every quadratic repeating factor of the type (ax 2 + bx + c) k , we assume :

Short cut Method of Finding the Constant of a Non-repeated Linear Factor in Denominator Let  
 




Definite Integrals
1. If f and F are two continuous functions defind on [a, b] such that 
then the number F(b) - F(a) is called definite integration of f between a and b and is denoted by 
i.e., 
This is called fundamental theorem of integral calculus. Here 'a' is called lower limit (LL) and 'b' is upper limit (U.L) and 
always. Also 
dx denotes algebric sum of the area bounded by curve y = f ( x ) , ordinates x = a, x = b and x - axis. 2. 
is always unique. is also defined as an infinite limit sum.. 4. Properties of Definite Integration:
1. 
2. 
3. 
where a < c < b 4. 
but converse need not be true 5. 
6. 
7. 
8. 
9. 
10. 
If but converse need not be true. 11. 
If but converse need not be true. 12. 
(change limit Theorem) 13. 
14. 
15. 
16. 
17. 
18. 
This is called Leibnitz rule . 19. 
where m and M are respectively the minimum and maximum values of f ( x ) in [ a, b ] 20. If f is a periodic function with period T , i.e., if f ( x + T ) = f ( x ) then a) 
b) 
c) 
where m, n are integers d) 
i.e., it is not dependent on 'a' 21. 
This is called cauchy - schwartz inequality
WALLI'S FORMULAE :
22.  23. Case (1)
: If m is odd and n is either even or odd 
Case (2) : If m is even and n is even 
Case (3) : If m is even and n is odd. 
Reduction Formulae on Definite Integration
: 24. If 
then 
(where n > 2) 25. If 
then 
26. If 
then 
27. If 
then 
28. By parts Formulae on Definite Integration :  29. If a function has finite number of points of discontinuties in [a, b] then the function is definite integrable in that interval. 30. Definite integration as infinite limit sum : 1) 
2) Working rule : Step I : First reduce the given infinite limt into the form 
Step II : Replace r/n with x and 1/n with dx Step III : Replace 

Note :
1) 
2) 
3) 
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